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To solve the equation \[ 3^x + 3^y + 3^z = 837, \] we begin by factoring 837. First, we divide 837 by 3: \[ 837 \div 3 = 279, \quad 279 \div 3 = 93, \quad 93 \div 3 = 31, \] which gives the factorization \[ 837 = […]