A dog running in an open field has components of velocity v_x=2.6 m/s and v_y=-1.8 m/s at t_1=10.0

A dog running in an open field has components of velocity v_x=2.6 m/s and v_y=-1.8 m/s at t_1=10.0 s.

For the time interval from t_1=10.0 s to t_2=20.0 s, the average acceleration of the dog has magnitude 0.45 m/s^2 and direction 31.0° measured from the +x-axis toward the +y-axis. At t_2=20.0 s,

[a] what are the x- and y-components of the dog’s velocity?
[b] What are the magnitude and direction of the dog’s velocity?
[c] Sketch the velocity vectors at t_1 and t_2. How do these two vectors differ?

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